Posted by Mischa on Thursday, January 24, 2008 at 4:24pm.
I will assume you mean (1/2)x and not 1/(2x)in the differential equation
dy/dx = m, so we require that
m = x/2 + mx+ b -1
This is true if m = -1/2 and
b = 1+m = 1/2
y = -x/2 + 1/2 is a solution, but not the only solution, to the differential equation.
dy/dx=(1/2)x + y - 1
I assume that is what you mean.
y = m x + b
dy/dx = m
m = .5 x + mx + b - 1
m = (.5 + m) x + b-1
well if m is to be constant, m must be -.5
-.5 = b-1
b = .5
y = -.5 x + .5
--------the end -----
Now check with m = -.5 and b = +.5
y = -.5 x + .5
dy/dx = -.5
dy/dx = .5 x + (-.5 x +.5) - 1
= +.5 - 1
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