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April 18, 2015

April 18, 2015

Posted by **sarah** on Wednesday, January 23, 2008 at 10:36pm.

(ln(x))/(x^2)

- calc -
**drwls**, Wednesday, January 23, 2008 at 11:46pmTry integration by parts.

Let u = ln x

du = dx/x

dv = 1/x^2 dx

v = -1/x

Integral of lnx/x^2 = Integral of udv

= uv - Integral of vdu

= -(ln x)/x - Integral of -dx/x^2

Take it from there, but check my work also

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