Posted by Kim on Wednesday, January 23, 2008 at 10:00pm.
Assume the 95 percent solution is made of 20 parts, one of which is water. The 70 percent will have six parts water. So add five parts water to the 95 percent, and you have it.
So you have 20 parts + 5 parts=350ml
25 parts= 350ml
1 part= 350/25 ml
So take five parts (5*350/25 ml) water, and the remaining 95 percent EtOH to the 350ml mark. If you dont have a mark,then add 350- 5*350/25 ml of EtOH.
check my thinking.
Related Questions
Chemistry -repost thank you in advance - I have a bottle of 95% ethanol ...
Chemistry - A solution of ethanol (C2H5OH) in water is prepared by dissolving 76...
chemistry - A solution of ethanol (C2H50H) in water is prepared by dissolving 76...
Chemistry - A solution of ethanol (C2H5OH) in water is prepared by dissolving 61...
Chemistry - An aqueous solution of ethanol is 14.1M C2H5OH. The density of the ...
Chemistry - The density of an aqueous solution containing 10% of ethanol (C2H5OH...
chem - A solution of ethanol (C2H5OH) in water is prepared by dissolving 57.0 mL...
chemistry - How much ethanol is required to make a 2L of a 70%ww solution?
chemistry - An aqueous solution of ethanol is 3.05 M in ethanol, CH3CH2OH. ...
chemistry - If a solution contains 255ml of ethanol in a 375 ml solution, what ...
For Further Reading
