Posted by ANITA on Wednesday, January 23, 2008 at 7:57pm.
Let C=number of chickens and P=number of pigs
1. C+P=18
2. P=18-C (isolate a variable)
3. 2C+4P=50 (Each chicken has two legs, each pig has four legs, and adds up to 50 legs).
4. 2C+4(18-C)=50) Substitute 18-C for P because step 2 shows P=18-C.
2C+72-4C=50
72-2C=50
-2C= -22
C=11
Related Questions
Maths - 1/3 of the total barn animals were chickens and rest were pigs there ...
6th grade math - on a farm there is 18 pigs and chickens (all together). There ...
math - A farmer has both chickens and sheep on his farm. He has a total of 25 ...
algebra - A farm raises a total of 220 chickens and pigs. The number of legs of ...
Algebra 1 - a farm raises a total of 220 chickens and pigs. The number of legs ...
Algebra - An algebra teacher drove past a farmyard that was full of chickens ...
Math - There are a total of 107 chickens and rabbits on a farm. The total number...
math - 52 legs, there are 16 animals, how many chickens and pigs are there
Algebra 1 - a farmer raises chickens and cows. there are 34 animals in all. the ...
math - Flamingos have 2 legs lions have 4 legs there are 72 animals totaling 200...
For Further Reading
