Posted by **Ricky** on Wednesday, January 23, 2008 at 12:32am.

yea it sais, three times one number added to another number is 18. twice the first number minus the other number is twelve.

find the numbers

- math -
**Quidditch**, Wednesday, January 23, 2008 at 12:51am
x=first number

y=second number

3*x + y = 18

2*x - y = 12

You need to eliminate one of the variables and solve for the remaining one. In this problem, you can see that if the two equations are added together, the y variable is eliminated:

adding:

3x + y = 18

2x - y = 12

---------------

5x + 0y = 30

5x = 30

x=6

plug the known x value into either equation to solve for y.

taking the first one...

3*6 + y = 18

rearrange to get

y = 0

- math -
**Ricky**, Wednesday, January 23, 2008 at 12:58am
hey thx man, i messed up that one cause i though added to another number ment it goes before it

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