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July 29, 2014

July 29, 2014

Posted by **FrustratedDad** on Tuesday, January 22, 2008 at 10:54pm.

(8(x^3y^4)2)-2

- Algebra -
**drwls**, Tuesday, January 22, 2008 at 11:06pmAre the last 2's exponents? That would mean you want to know

[8(x^3y^4)^2]^-2

The +2 and -2 operations on (x^3y^4) would leave it unchanged, and leave you with

(1/64)(x^3y^4)

- Algebra -
**FrustratedDad**, Tuesday, January 22, 2008 at 11:56pmThe 2's are not exponents

- Algebra -
**FrustratedDad**, Wednesday, January 23, 2008 at 12:04amApologies to you and James B, I'm home from work now and just looked at the problem and the 2's are exponents.

- Algebra -
- Algebra -
**james b**, Tuesday, January 22, 2008 at 11:38pmThe problem to solve is:

(8(x^3y^4)2)-2

Multiply 8 and

8*(x^3*y^4)2 evaluates to 64

Abort (8*(x^3*y^4)2)-2 evaluates to 64-64

The final answer is 64-64

- Algebra -
**FrustratedDad**, Wednesday, January 23, 2008 at 12:05amApologies, I'm home from work now and was able to look at the problem for myself and the 2's are exponents.

- Algebra -
- Algebra -
**drwls**, Wednesday, January 23, 2008 at 2:15amIf the 2's are exponents, I stand by my original answer.

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