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Algebra

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please help me simplify
(8(x^3y^4)2)-2

  • Algebra - ,

    Are the last 2's exponents? That would mean you want to know
    [8(x^3y^4)^2]^-2
    The +2 and -2 operations on (x^3y^4) would leave it unchanged, and leave you with
    (1/64)(x^3y^4)

  • Algebra - ,

    The 2's are not exponents

  • Algebra - ,

    Apologies to you and James B, I'm home from work now and just looked at the problem and the 2's are exponents.

  • Algebra - ,

    The problem to solve is:
    (8(x^3y^4)2)-2

    Multiply 8 and
    8*(x^3*y^4)2 evaluates to 64

    Abort (8*(x^3*y^4)2)-2 evaluates to 64-64
    The final answer is 64-64

  • Algebra - ,

    Apologies, I'm home from work now and was able to look at the problem for myself and the 2's are exponents.

  • Algebra - ,

    If the 2's are exponents, I stand by my original answer.

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