Posted by FrustratedDad on .
please help me simplify
(8(x^3y^4)2)2

Algebra 
drwls,
Are the last 2's exponents? That would mean you want to know
[8(x^3y^4)^2]^2
The +2 and 2 operations on (x^3y^4) would leave it unchanged, and leave you with
(1/64)(x^3y^4) 
Algebra 
FrustratedDad,
The 2's are not exponents

Algebra 
FrustratedDad,
Apologies to you and James B, I'm home from work now and just looked at the problem and the 2's are exponents.

Algebra 
james b,
The problem to solve is:
(8(x^3y^4)2)2
Multiply 8 and
8*(x^3*y^4)2 evaluates to 64
Abort (8*(x^3*y^4)2)2 evaluates to 6464
The final answer is 6464 
Algebra 
FrustratedDad,
Apologies, I'm home from work now and was able to look at the problem for myself and the 2's are exponents.

Algebra 
drwls,
If the 2's are exponents, I stand by my original answer.