algebra 2
posted by supreme .
6(u+5)^2=120

5 + or  4i squareroot 5

5 to both sides?
so what about the u?
in the parenthises with the five, what happens to that? 
Take the (u+5)^2 and solve (u+5)(u+5)
that gives you 6(u^210u25)=120
then distribute the 6
6u^260u150= 120 then subtract 120 from both sides
6u^260u270=0 then divide everythin by 6 giving you
u^2+10u+45=0 then use the quadratic formula
(b +/ squareroot b^2 4ac)/2a
then you will get the answer. If you don't know how to use the quadratic formula then let me know.