Friday

October 24, 2014

October 24, 2014

Posted by **Daisy** on Tuesday, January 22, 2008 at 2:18am.

- Calculus -
**Count Iblis**, Tuesday, January 22, 2008 at 9:18amI would advice to take out the 1/x^2 term first:

(3x - (2/x^2))^8 =

1/x^16 (3 x^3 - 2)^8 =

So you need to get x^18 from the expansion of the bracket:

(3 x^3 - 2)^8 contains a term:

(3 x^3)^6 (-2)^2 Binomial(8,6)

So, the coefficient is 81648.

**Answer this Question**

**Related Questions**

Calculus - Find the constant term in the expansion of [x + (3/x squared)]^9 Find...

Pre Calculus 12 urgent - andrew is working on a binomial problem (1/2x-y)^7. He ...

Algebra2/trig - Hi, I can't figure out what I'm supposed to do on this problem. ...

pre-calculus - Find the designated term of the binomial expansion. 5th term of (...

algebra - Find the coefficient of the fifth term in the expansion(rootK+3)^8

Math - What is the coefficient of the fifth term in the expansion of (x + 1)^8?

Pre calculus - 1. convert polar equation to rectangular coordinates: r^2=...

Integrated Math 1 - What is the coefficient of the xy^2 term in the expansion of...

Math binomial formula and sequence - a) use the binomial formula to find the 5th...

Math - 2x^3 + 3x^2 + x + 1 dx --------------------- -2x + 1 [2x^3 + 3x^2 + x...