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December 18, 2014

December 18, 2014

Posted by **Daisy** on Tuesday, January 22, 2008 at 2:18am.

- Calculus -
**Count Iblis**, Tuesday, January 22, 2008 at 9:18amI would advice to take out the 1/x^2 term first:

(3x - (2/x^2))^8 =

1/x^16 (3 x^3 - 2)^8 =

So you need to get x^18 from the expansion of the bracket:

(3 x^3 - 2)^8 contains a term:

(3 x^3)^6 (-2)^2 Binomial(8,6)

So, the coefficient is 81648.

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