Posted by Samir on Monday, January 21, 2008 at 8:48pm.
first the driver in the driver seat
4 possible
that leaves three with the other three to choose the other six seats. How many arrangements of those six people?
the first one has 6 choices, the second 5 choices .....
6*5*4 etc or 6!
so 4 * 6!
even ends in 2 , 4 , 6
so the fifth digit must be 2, 4, or 6
the fourth must be 1, 2 , 3 , 4 , 5 ,6 , 7 seven choices
the third - 7 choices
the second -- 7 choices
he first - 7 choices
so
2 * 7^4
3*7^4
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