Sunday

April 20, 2014

April 20, 2014

Posted by **Jujube** on Monday, January 21, 2008 at 12:05pm.

- math PLEASE HELP -
**Reiny**, Monday, January 21, 2008 at 2:19pmthe diagonals of a rhomus bisect each other at right angles, forming 4 equal right-angled triangles

the hypotenuse of each is 96/4 or 24 and one side is 32/2 or 16.

so by Pythagoras, the other side is sqrt(320)

The centre of the incsribed circle is at the intersection of the diagonals, so I drew a height inside one of the triangles.

by some basic geometry I found the r^2 = 1280/9

so the area of the circle is pi*1280/9 but that is given to be k*pi/w

so k*pi/w = pi*1280/9

since 1280/9 is relatively prime, k+w = 1280+9 = 1289

**Related Questions**

math-geometry - 1. A rhombus has a perimeter of 96, and the length of one of its...

Math - Which of the following statements is not always true? A. In a rhombus, ...

geometry - The diagonals of a rhombus are in 2:1. If the perimeter of the ...

maths - the length of the diagonals of a rhombus are 24cm and 32cm. the ...

math - The diagonals of a rhombus have lenghts 16 and 30. Find the perimeter of ...

circles - OPQR is a rhombus , three of whose vertices lie on a circle with ...

geometry - Given: QRST is a parallelogram. Prove: QRST is a square. Complete ...

Geometry - Find the area of the rhombus: In rhombus ABCD, AB=11 and AC=13. Find ...

Geometry - Find the area of the rhombus: In rhombus ABCD, AB=11 and AC=13. Find ...

Math (Geometry) - 1. A rhombus has an area of 5 square meters and a length of 3 ...