Thursday
July 24, 2014

Homework Help: physics

Posted by Hannah on Sunday, January 20, 2008 at 9:00pm.

A particle moves in a circle in such a way that the x- and y-coordinates of its motion are given in meters as functions of time t in seconds by:
x=5cos(3t)
y=5sin(3t)
What is the period of revolution of the particle?

Here's what my train of thought was... dy/dt over dx/dt would equal dy/dx which equals velocity. So velocity would be -cot(3t). But then how do I find r? Plus none of the answers here have a trig function in them... ???????

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