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September 16, 2014

September 16, 2014

Posted by **Hannah** on Saturday, January 19, 2008 at 10:49pm.

- physics -
**drwls**, Saturday, January 19, 2008 at 11:06pmThe centripetal acceleration of a satellite in a circular orbit is V^2/R , but V is a function of R also. For an earth satellite

GM/R^2 = V^2/R

where g is the universal constant of gravity and M is the mass of the earth. Therefore

V^2 = GM/R, and V^2 is inversely proportional to R.

That means that the acceleration V^2/R is inversely proportional to R^2. So if R2 = 2 R1, the acceleration at 2 is 1/4 as much.

I could have obtained this result more easily by recognizing that the acceleration is the gravitation force divided by satellite mass m, and the force is inversely proportional to R^2.

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