In,the,ideal,apparatus,m1=2.0kg,What,is,m2,if,both,mass,are,at,rest?,How,about,if,both,masses,are,moving,at,constant,velocity?,angle,is,37,deg,and,ther,is,gravity

I am afraid I can not see your experiment.

However as a rule a constant velocity has no effect on forces since force is proportional to rate of change of velocity (acceleration).

To determine the value of m2 in the ideal apparatus, where m1 = 2.0 kg and both masses are at rest, we need to consider Newton's second law of motion and the concept of equilibrium.

When both masses are at rest, it means that the system is in equilibrium, and the forces acting on each mass are balanced. In this case, we only need to take into account the force of gravity.

1. Determine the force of gravity acting on m1:
F1 = m1 * g, where g is the acceleration due to gravity (approximately 9.8 m/s^2).

2. Since the system is in equilibrium, the force experienced by m1 due to m2 is equal in magnitude and opposite in direction to the force experienced by m2 due to m1. Hence, the forces are balanced.

3. Set up the equation for equilibrium:
F1 = F2, where F2 represents the force experienced by m2 due to m1.

4. Replace the force values with their respective equations:
m1 * g = m2 * g

5. Simplify and solve for m2:
m2 = m1 = 2.0 kg

Therefore, if both masses are at rest, the value of m2 will also be 2.0 kg.

Now, let's consider the scenario where both masses are moving at a constant velocity and an angle of 37 degrees with respect to the horizontal axis.

6. In this case, we need to consider the force of gravity acting on each mass as well as the tension in the string connecting them.

7. Decompose the gravitational force acting on m1 into its horizontal and vertical components:
F1_horizontal = m1 * g * sin(theta), where theta represents the angle (37 degrees).
F1_vertical = m1 * g * cos(theta)

8. Since the system is moving at a constant velocity, the net force acting in the horizontal direction is zero. Therefore, the tension in the string, T, is equal in magnitude and opposite in direction to F1_horizontal.

9. Set up the equation for the horizontal equilibrium:
T = m2 * g * sin(theta)

10. Simplify and solve for m2:
m2 = T / (g * sin(theta))

Please note that to determine the actual value of m2, you would need to know the tension in the string, which would depend on other factors such as the nature of the pulley system or any additional forces acting on the system.