80 N and 60 N force act concurrently on a point. find magnitude of the vector sum if the forces pull
-in the same direction
-in opposite direct.
-at right angles to each other
seriously, i don't understand what you are supposed to do
What does concurent mean? In the same direction?
What does opposite mean?
If at right angles, you have to use the pyth theorem.
http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/vectors/u3l1b.html
No worries, I'm here to help explain how to solve this problem.
To find the magnitude of the vector sum, you need to use vector addition. It involves adding the forces together using certain rules depending on the direction in which they act.
1. When the forces pull in the same direction:
In this case, you directly add the magnitudes of the forces to get the magnitude of the vector sum. So, the magnitude of the vector sum would be 80 N + 60 N = 140 N.
2. When the forces pull in opposite directions:
In this situation, you subtract the smaller force from the larger force. The magnitude of the vector sum is the difference between the magnitudes of the two forces. So, the magnitude of the vector sum would be |80 N - 60 N| = |20 N| = 20 N.
3. When the forces act at right angles to each other:
When forces act at right angles, you can use the Pythagorean theorem to find the magnitude of the vector sum. Square the magnitudes of each force, then add them together and take the square root of the sum.
To calculate the magnitude of the vector sum in this case:
Magnitude of Force 1 = 80 N
Magnitude of Force 2 = 60 N
Magnitude of vector sum = √(80^2 + 60^2) = √(6400 + 3600) = √10000 = 100 N
So, when the forces act at right angles to each other, the magnitude of the vector sum is 100 N.
Remember, vector addition involves considering both the magnitudes and directions of the forces.