im not sure how to do this question

80 N and 60 N force act concurrently on a point. find magnitude of the vector sum if the forces pull
-in the same direction
-in opposite direct.
-at right angles to each other

thanks

You don't need to use cosines and sines for this. If the forces are in the same direction, that add. If they are in opposite directions, subtract one from the other. If they are at right angles, use the Pythagorean theorem

We will be happy to critique your thinking on this.

i don't understand..

do u use cos and sin?

i don't understand the question.

Find resultant force if the 80 N is acting to the right and is at right angles to the 60 N force

To solve these types of problems, you can use vector addition. The magnitude of the vector sum is determined by adding the magnitudes of the individual forces, taking into account their direction. Let's break down the problem step by step for each scenario:

1. Forces pulling in the same direction:
In this case, the two forces are acting in the same direction. To find the magnitude of the vector sum, simply add the magnitudes of the forces:
Magnitude of the vector sum = 80 N + 60 N = 140 N

2. Forces pulling in opposite directions:
When the two forces act in opposite directions, you need to subtract the smaller force from the larger force. The magnitude of the vector sum is then given by:
Magnitude of the vector sum = |80 N - 60 N| = 20 N (Note: the absolute value is used to ensure a positive result, as magnitude can't be negative)

3. Forces acting at right angles to each other:
When forces act at right angles to each other, you can use the Pythagorean theorem. The magnitude of the vector sum is equal to the square root of the sum of the squares of the magnitudes of the two forces:
Magnitude of the vector sum = √(80 N^2 + 60 N^2) = √(6400 N^2 + 3600 N^2) = √10000 N^2 = 100 N

By following these steps, you should be able to find the magnitude of the vector sum for each scenario.