Posted by Hannah on Thursday, January 17, 2008 at 10:29pm.
Its average speed is distance over time, or 1 m/s. Since its initial speed is zero, its final speed vf1 is 2m/s to get that average.
Now, the acceleration:
a=changevelocity/time. Compute acceleration.
Now, assume that acceleration is constant.
distance1to2= distanceattime2-distanceattime1
= 2m/s*1sec+1/2 a*2^2 - (1/2 a*1^2)
Related Questions
physics - Objects of masses m1 = 4.00 kg and m2 = 9.00 kg are connected by a ...
physics - Objects of masses m1 = 4.00 kg and m2 = 9.00 kg are connected by a ...
physics - Objects of masses m1 = 4.00 kg and m2 = 9.00 kg are connected by a ...
physics - A frictionless30degrees incline should provide an acceleration of 4....
physics - Objects of masses m1 = 4.00 kg and m2 = 9.00 kg are connected by a ...
physics - Objects of masses m1 = 4.00 kg and m2 = 9.00 kg are connected by a ...
physics - Objects of masses m1 = 4.00 kg and m2 = 9.00 kg are connected by a ...
physics - A block of mass m = 2.00 kg is released from rest at h = 0.400 m from...
physics - a mass is released from rest from a height of 4m. it slides down a ...
physics - A 0.50-kg block, starting at rest, slides down a 30.0° incline ...
For Further Reading