Thursday

April 17, 2014

April 17, 2014

Posted by **Lindsay** on Wednesday, January 16, 2008 at 10:38pm.

Can someone at least tell me where to begin? I'm lost when it comes to these types of problems.

- Physics -
**Damon**, Thursday, January 17, 2008 at 4:30amvertical direction equations:

v = Vo sin 42 -9.8 t

or

v = .669 Vo - 9.8 t

h = Ho + .669 Vo t - 4.9 t^2

Horizontal direction equation

x = (Vo cos 42 ) t

or

x = .743 Vo t

Now horizontal fact

135 = .743 Vo t

And vertical

23 = 0 + ,669 Vo t - 4.9 t^2

from horizontal equation

Vo t = 182

use that in vertical equation

23 = .669 (182) - 4.9 t^2

4.9 t^2 = 98.8

t = 4.49 seconds in air

so Vo = 182/4.49

Vo = 40.5 m/s

Now impuse = change of momentum

F d = m Vo

F (1.28) = .125 (40.5)

solve for F

**Related Questions**

Physics - An archer shoots an arrow that leaves the bow at an angle of 42 ...

Physics - An archer stands a horizontal distance d= 55 m away from a tree sees ...

physics - An arrow is shot from a bow at 20.0 m/s at an angle of 65 degrees ...

physics - An archer standing a horizontal distance d=50m away from a tree sees ...

physics - You have a friend who is an archer and she wants to know how fast the ...

physics - You have a friend who is an archer and she wants to know how fast the ...

physics - An archer shoots a 54.6 g arrow horizontally at a target 14.0 m away. ...

Physics - An archer shoots an arrow horizontally at a target 12 m away. The ...

physics - an archer at the edge of a cliff fires an arrow from a height of 14.6 ...

physics - an archer at the edge of a cliff fires an arrow from a height of 14.6 ...