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February 1, 2015

February 1, 2015

Posted by **Lindsay** on Wednesday, January 16, 2008 at 10:38pm.

Can someone at least tell me where to begin? I'm lost when it comes to these types of problems.

- Physics -
**Damon**, Thursday, January 17, 2008 at 4:30amvertical direction equations:

v = Vo sin 42 -9.8 t

or

v = .669 Vo - 9.8 t

h = Ho + .669 Vo t - 4.9 t^2

Horizontal direction equation

x = (Vo cos 42 ) t

or

x = .743 Vo t

Now horizontal fact

135 = .743 Vo t

And vertical

23 = 0 + ,669 Vo t - 4.9 t^2

from horizontal equation

Vo t = 182

use that in vertical equation

23 = .669 (182) - 4.9 t^2

4.9 t^2 = 98.8

t = 4.49 seconds in air

so Vo = 182/4.49

Vo = 40.5 m/s

Now impuse = change of momentum

F d = m Vo

F (1.28) = .125 (40.5)

solve for F

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