Posted by courtney on Wednesday, January 16, 2008 at 3:23pm.
This is fairly easy on a polar graph. Draw vectors1 and 2, and a line representing the direction of movement.
graphically add 1 and 2, getting a resultant r.
Now r added to some third vector must equal someting along the line for the movement at 15N of E. You will need a polar graph, straight edge, probably a compass. A parallel motion protractor would make it easy, but they are not so available today.
Have fun.
I dont have a polar graph, never even heard of it. Is there any way to do this with equations?
Polar graph is pretty common.
http://mason.gmu.edu/~mmankus/Handson/polar.htm
The equations are messy.
k I'll try it, thanks.
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