Posted by **Kristiane** on Tuesday, January 15, 2008 at 4:14pm.

I need help on factoring monomials in quadratic form.

The problem is:

aČ + 17a + 16

I know that the first step is to multiply 16 times the coefficient of "a", which is 1. I get 16.

Now I have to fill in factors that when multiplied, equal 16, but when added, equal 17.

So now I have 16 x 1 = 16

and 16 + 1 = 17.

And now I have to fill in the addition factors to make aČ + 16a + 1a + 16.

I am just confused as to what to do next to solve the problem.

- Math -
**Reiny**, Tuesday, January 15, 2008 at 5:08pm
from your

aČ + 16a + 1a + 16 use grouping

a(a+16) + 1(a+16)

=(a+16)(a+1)

you could also have arranged your terms this way

aČ + 1a + 16a + 16

=a(a+1) + 16(a+1)

=(a+1)(a+16)

- Math -
**Kristiane**, Tuesday, January 15, 2008 at 5:50pm
Oh, okay! I understand now. Thank you!

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