Posted by Kristiane on Tuesday, January 15, 2008 at 4:14pm.
I need help on factoring monomials in quadratic form.
The problem is:
aČ + 17a + 16
I know that the first step is to multiply 16 times the coefficient of "a", which is 1. I get 16.
Now I have to fill in factors that when multiplied, equal 16, but when added, equal 17.
So now I have 16 x 1 = 16
and 16 + 1 = 17.
And now I have to fill in the addition factors to make aČ + 16a + 1a + 16.
I am just confused as to what to do next to solve the problem.
- Math - Reiny, Tuesday, January 15, 2008 at 5:08pm
aČ + 16a + 1a + 16 use grouping
a(a+16) + 1(a+16)
you could also have arranged your terms this way
aČ + 1a + 16a + 16
=a(a+1) + 16(a+1)
- Math - Kristiane, Tuesday, January 15, 2008 at 5:50pm
Oh, okay! I understand now. Thank you!
Answer this Question
More Related Questions
- Math (Algebra 2) - Factoring by Using a Quadratic Form Problem: x^4 + 8x^2 - 20 ...
- Algebra II factoring - I need help. i am having trouble factoring trinomials ...
- Algebra 2 - I need to know how to solve quadratic equations by factoring. Can ...
- math - My problem I have involves a method that requires using the quadratic ...
- Math - How do you multiply monomials without an exponent as one of the numnbers...
- Algebra - Solve the equation. Use factoring or the quadratic formula, whichever ...
- Algebra - Can someone please help me with math problem and explain to me step by...
- Math - Use the quadratic formula to solve each of the following quadratic ...
- algebra - Can someone please show me how to solve this problem step by step ...
- math (factoring quadratic trinomials) - i am doing factoring with quadratic ...