Posted by Kristiane on Tuesday, January 15, 2008 at 4:14pm.
I need help on factoring monomials in quadratic form.
The problem is:
aČ + 17a + 16
I know that the first step is to multiply 16 times the coefficient of "a", which is 1. I get 16.
Now I have to fill in factors that when multiplied, equal 16, but when added, equal 17.
So now I have 16 x 1 = 16
and 16 + 1 = 17.
And now I have to fill in the addition factors to make aČ + 16a + 1a + 16.
I am just confused as to what to do next to solve the problem.
- Math - Reiny, Tuesday, January 15, 2008 at 5:08pm
aČ + 16a + 1a + 16 use grouping
a(a+16) + 1(a+16)
you could also have arranged your terms this way
aČ + 1a + 16a + 16
=a(a+1) + 16(a+1)
- Math - Kristiane, Tuesday, January 15, 2008 at 5:50pm
Oh, okay! I understand now. Thank you!
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