a cue stick strikes a stationary pool ball, exerting an average forece of 50 N over a time of 7 milliseconds. If the ball has mass .1kg, what speed does it have just after impact?
change in momentum = force* time
which is sometimes called "impulse"
m (Vfinal -Vinitial) = F * t
if m is constant and F is constant
here Vinitial is given as zero and you know everything but Vfinal so you can solve for Vfinal
To find the speed of the pool ball just after impact, we can use the equation for average force:
Average force (F_avg) = mass (m) * acceleration (a)
In this case, the average force exerted by the cue stick is given as 50 N, and the mass of the ball is 0.1 kg. We need to find the acceleration to calculate the speed, so we rearrange the equation:
acceleration (a) = F_avg / m
Substituting the given values:
acceleration (a) = 50 N / 0.1 kg
Now, we need to find the final velocity using the equation:
Final velocity (v) = Initial velocity (u) + acceleration (a) * time (t)
The initial velocity of the ball is assumed to be zero because it is stationary. The time of impact given is 7 milliseconds, which should be converted to seconds:
time (t) = 7 milliseconds = 7 * 10^(-3) seconds
Substituting the values into the equation:
Final velocity (v) = 0 + acceleration (a) * 7 * 10^(-3) seconds
Finally, calculate the final velocity:
Final velocity (v) = acceleration (a) * 7 * 10^(-3) seconds
Note: The value of acceleration calculated earlier should be used here.
This calculation will give you the speed of the pool ball just after the impact.