Posted by Anonymous on Sunday, January 13, 2008 at 6:54pm.
i don't understand how to do this question, its a phys 11:
"A skier is acc. down a 30.0 degree hill at 3.80m/s^2"
a) What is the horiz. comp. of the acc.?
b) What is the vert. comp. of the acc.?
c) Assuming she starts from rest and acc. uniformly down hill, how long will it take for her to reach bottom if the elev. change is 355m?

physics  Damon, Sunday, January 13, 2008 at 7:06pm
a) 3.80 cos 30
b) 3.80 sin 30 if + is up
c) only vertical component matters for change in elevation
y = Yo + Vo t + (1/2) a t^2
355 = 0 + 0 t + (.5)(1.90) t^2
you can solve that I am sure. 
physics  Anonymous, Sunday, January 13, 2008 at 7:08pm
thanks