If I know the number of sides of a regular polynomial(10), how do I find the exterior and interior angles?
Do you mean polygon? If so, this is how you figure out both:
Interior (sum):
(n-2)180
(10-2)180
(8)180
1440
Then divide this number by the number of sides.
1440/10=144.
Exterior (sum):
Since the exterior angle sum of any regular polygon is 360, divide this number by the number of sides.
360/10=36.
I hope this works for you!