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September 18, 2014

September 18, 2014

Posted by **Ashlynn** on Sunday, January 13, 2008 at 6:22pm.

Factor completely:

1. 8x3 + 2x3 – 12x –3

2. 27x3+8

3.125 – 8x3

- Algebra -
**bobpursley**, Sunday, January 13, 2008 at 6:51pmThe second one is the sum of perfect cubes, for which you have a formula.

The third is the difference of perfect cubes, same formula almost.

The first I assume is 8x^3+2x^2-12x-3=0 This is not going to factor nicely, I suggest you graph it on your calculator, and take a look at the roots. Not a nice function.

- Algebra -
**Ashlynn**, Sunday, January 13, 2008 at 7:27pmI don't have a graphing calculator. Is there another way to find the roots so I can factor the problem? And I'm sorry I don't know what formula you are talking about for 1 and 2.

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