physics rewrite
posted by ashley on .
starting from rest, a ball rolls, down an incline at a constant acceleration of 2meters per second squared
what is the velocity of the ball after 8.5 seconds?
how far does the ball roll in 10 seconds?
any one can help pleasse im stuck
show n detail how to find the answer

v = Vo + a t
x = Xo + Vo t + (1/2) a t^2
here
Vo = initial velocity = 0
Xo = initial position = 0
a = 2
t=8.5 in part 1 (first equation for v)
t = 10 seconds for part 2 (second equation for x)
try it from there