Algebra
posted by Danielle .
Divide using long division: 6x3 + 19x2 + x – 10 divided by 2x 1
Divide using synthetic division: 2x3 + 2x2 + 10 divided by x + 3
PLEASE HELP!

ans.__________________
2x1 6x^3 +19 x^2 +x 10
ans. 3 x^2
________________________
2x1 6x^3 +19 x^2 +x 10
______6x^3 ______________
ans. 3 x^2
________________________
2x1 6x^3 +19 x^2 +x 10
______6x^3  3 x^2 ______________
_______0 +22 x^2 +x 10
ans. 3 x^2 +11 x
________________________
2x1 6x^3 +19 x^2 +x 10
______6x^3  3 x^2 ______________
_______ 0 +22 x^2 + x 10
___________+22 x^2 11x____
___________________12x 10
ans. 3 x^2 +11 x +6
________________________
2x1 6x^3 +19 x^2 +x 10
______6x^3  3 x^2 ______________
_______ 0 +22 x^2 + x 10
___________+22 x^2 11x____
___________________12x 10
___________________12 x6
R = 4
=============================
_______2 2 0 10
3_________________________
_______2
_______2 2 0 10
________6
3_________________________
_______2
_______2 2 0 10
________6
3_________________________
_______2 4
_______2 2 0 10
________6 12
3_________________________
_______2 4
_______2 2 0 10
________6 12
3_________________________
_______2 4 12
_______2 2 0 10
________6 12 36
3_________________________
_______2 4 12
_______2 2 0 10
________6 12 36
3_________________________
_______2 4 12 26
so
2x^2 4x +12 remainder 26 
I'm a little confused by this. What is the answer to #1 or is 2x^24x+12 remainder 26 the answer? If so then how do I solve for #2? I'm sorry just some things come out funny when typed.

The answer to #1 is 3x^2+11x+6 remainder 4
Here is the last line of #1
ans. 3 x^2 +11 x +6
________________________
2x1 6x^3 +19 x^2 +x 10
______6x^3  3 x^2 ______________
_______ 0 +22 x^2 + x 10
___________+22 x^2 11x____
___________________12x 10
___________________12 x6
R = 4
then I put a line like this
==================================
and went on with the synthetic division.
In both cases I tried to only put one thing at a time, so copied over and over getting a little further into the problem each time
The answer to the synthetic division one is
2 x^2  4x + 12 reminder is 26 
Here is the final version of the synthetic division one:
_______2 2 0 10
________6 12 36
3_________________________
_______2 4 12 26
so
2x^2 4x +12 remainder 26
like bring the 2 down
3*that 2 = 6
26 goes below as 4
3*4 = +12  that goes below the 0
0+12 = 12, bring it down
3*12 = 36
add that to 10 to get remainder of 26 
2x3 + 2x2 + 10
By the way, important to write that as
2x^3 +2x^2 + 0x + 10
If you leave the zero coefficient terms of the polynomial out, you get messed up worse with columns and such. That is exactly why they had no coefficient of x, to make you figure that out.