Posted by Amy on Saturday, January 12, 2008 at 5:27pm.
I assume you know how to complete the square
-10 x^2 + 6 x = 0.9
x^2 -.6 x = -0.09
x^2 -.6 x + .09 = -.09+.09 = 0
(x-.3)^2 = 0
x = .3 sure enough.
x^2 -.6 x = -0.09 or just rearrange and factor
x^2 - .6 x + 0.09 = 0
(x-.3)(x-.3) = 0
x = .3 and x = .3
oh, okay, I see what you're doing. I just have one question, though;why is it that when you get rid of the -10, the 6 is affected by it? I would assume that it would be left alone...
Or use quadratic equation
-10 x^2 + 6 x = 0.9
-10 x^2 + 6 x -.9 = 0
a = -10
b = 6
c = -.9
x = [-6 +/- sqrt (36-36) ]/-20
=-6/-20
=-3/-10
= 0.3
I divided both sides of the equation - ALL TERMS by -10
-10 x^2 + 6 x
---------------
-10
= x^2 -.6 x
oh, no wonder nothing worked out; thanks!
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