Please post questions like this separately, not in groups.
Rewrite your equations, which are correct, as
X + Y + Z = 54
X + 2Y + 3Z= 97
X + 3Y + 2Z= 149
Subtract the first eq. from the second.
Y + 2Z = 43
Subtract the first eq. from the third
2Y + Z = 95
Double the last one
4Y + 2Z = 190
Get rid of the Z terms
3Y = 190 - 43 = 147
Y = 49
49 + 2Z = 43
Z = -3
X + 49 -3 = 54
X = 8
The largest number is Y.
let D, N and Q represent the number of dimes, nickels and quarters respectively.
then 10D + 5N + 25Q = 400 and
10(3N) + 5(N/2) + 25(Q+6) = 550
there has to be more information given to continue with this question, e.g perhaps you made a typo and the first part included the total number of coins in the box.
Let the amount of the current liquid to be drained and replaced by pure water be x quarts
Looking only at the water content in the rad...
.25(14-x) + x = .4(14)
solving this I got x = 2.8 quarts
#2 of 3
The original 14 gallons is 1/4 water, so it contains 3.5 gallons of water.
When you are done removing and replacing x gallons of the mix with water, you still have 14 gallons, but it is 40% water, so that makes 5.6 gallons of water in the radiator afterwards. The equation you have to solve is:
Initial water present + water removed -water added = final amount of water
3.5 - 0.25 x + x = 5.6
0.75 x = 2.1
x = 2.8 gallons
10d +5n divided which expression represents the money about among 5 in cents each persons recieves
i dont know the answer
en 100 platos cuantos litro de agua dentran
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