Wednesday

April 16, 2014

April 16, 2014

Posted by **Anonymous** on Thursday, January 10, 2008 at 7:33pm.

y = 3(x - 1)^2, x >= 1

Work:

x = 3(y - 1)^2

x = 3(y - 1)(y - 1)

x = 3(y^2 - y - y + 1)

x = 3y^2 - 6y + 3

And now what do I do!? Please explain and show me how to solve this inverse function!

...

Thank you

- Math - Inverse Functions -
**Damon**, Thursday, January 10, 2008 at 7:55pmx = 3(y - 1)^2 would be the inverse but you forgot the second part, y>=1

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