# trigonometry

posted by
**Hellga**
.

Please solve this equation. As you write down the steps, please give me a description on what you did.

y^3 - 16y^1/2 + 64 = 0

posted by
**Hellga**
.

Please solve this equation. As you write down the steps, please give me a description on what you did.

y^3 - 16y^1/2 + 64 = 0