Posted by **gq** on Wednesday, January 9, 2008 at 8:07pm.

2y^3-10y^2+12y...need to factor again..i got to the second step...

2y(y^2-5y+6)...think thats right but i don't get how to factor that out..help plz..

- algebra 2..again -
**drwls**, Wednesday, January 9, 2008 at 8:23pm
Go for one more factoring step and you get

2 y (y-2)(y-3)

- algebra 2..again -
**Jason**, Wednesday, January 9, 2008 at 8:45pm
Try it this way...

2y^3 - 10y^2 + 12y

Switch A&C to make it easier (always acceptable, just remember to keep your signs):

12y - 10y^2 + 2y^3

Factor out a GCF, in this case it's 2y:

2y(6 - 5y + y^2)

Next, factor a trinomial:

2y(2 - 1y)(3 - 1y)

This trinomial is your final answer.

Hope this helps you!

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