I'm not surprised the answer was wrong.
Chemical reactions are by mols and not by grams; therefore, 1 mol of each reactant produces 1 mol of each product but a mol is not a gram.
SO, convert 0.5839 g KHC2O4 to mols, convert mols KHC2O4 to mols KOH (that's the 1:1 part), then calculate the molarity of KOH. Post your work if you get stuck. I expect you will have no trouble.
when i converted KHC204 to mols, i got 0.00455 mols. when i divide that by the total volume (0.05699 L), i get 0.08, however, the answer is supposed to be 0.142.
Sorry I took so long to get back to you. It helps to post your work. Then we can catch the error. As it is I have no idea where the error is.
mols KHC2O4 = 0.5839/128.126 = 0.004557.
mols KHC2O4 = mols KOH
M KOH = mols/L
M KOH = mols KOH/Liters OF KOH (NOT TOTAL VOLUME). Now I know where the error is.
M KOH = 0.004557/0.03199 = 0.14246 which rounds to 0.1425 to four significant figures.
You may be thinking, "but the extra volume of other materials DID dilute the KOH " (and that is correct) but it also diluted the other materials at the same time. If you want to calculate it that way then change the molarities etc for all of the other components and the answer will come out to the same 0.1425. But the EASY way to look at the problem is this==and it's worth remembering. It isn't the volume that is reacting. It's the mols of one plus the moles of the other and you want to know the molarity at the BEGINNING of the titration and not at the end of the titration. I hope this helps.
To find the molarity of KOH, we need to follow the steps you mentioned:
1. Convert 0.5839 g of KHC2O4 to moles.
To do this, we use the molar mass of KHC2O4, which is 128.17 g/mol.
moles = mass (in grams) / molar mass
moles KHC2O4 = 0.5839 g / 128.17 g/mol
moles KHC2O4 = 0.00455 mol
So, you calculated the moles of KHC2O4 correctly.
2. Convert moles of KHC2O4 to moles of KOH.
Based on the balanced chemical equation, the stoichiometry between KHC2O4 and KOH is 1:1. This means that for every mole of KHC2O4, we have an equal number of moles of KOH.
moles KOH = moles KHC2O4
moles KOH = 0.00455 mol
Again, you are correct in this step.
3. Calculate the molarity of KOH.
Molarity (M) is defined as moles of solute divided by volume of solution in liters.
molarity = moles KOH / volume (in liters)
molarity = 0.00455 mol / 0.05699 L
molarity ≈ 0.08 M
Based on your calculations, you've also arrived at 0.08 M for the molarity of KOH. However, the correct answer appears to be 0.142 M.
To troubleshoot this, please double-check your volume measurement. Ensure that you have the accurate and precise volume of the solution, as even a slight change in volume can affect the final molarity calculation.