Posted by Courtney hey damon can i get the quadratic on this on Wednesday, January 9, 2008 at 2:37pm.
Consider a spaceship located on the EarthMoon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from each celestial body exactly cancel, leaving the craft literally weightless. Take the distance between the centers of the Earth and Moon to be 3.92E+5 km and the MoontoEarth mass ratio to be 1.200E2. What is the spaceship's distance from the center of the Moon?

PHYSICS  drwls, Wednesday, January 9, 2008 at 3:23pm
you don't need the q
Let M1 = moon mass; M2 = Earth mass,
r = distance from spaceraft to moon, and
D = Earthmoon distance
When the two gravity pulls are equal,
M1/r^2 = M2/(Dr)^2
[(Dr)/r]^2 = M2/M1 = 1/(0.012)
(Dr)/r = 9.13 = R/r 1
D/r = 10.13
Look up D and compute r.
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