What is the is product of
Nickel(II) nitrate+sodium phosphate
This is what I have:
Ni(NO3)2+Na3PO4---->
can you help me on the resultant equation please
Yes, I can help you with that! To determine the product of Nickel(II) nitrate and sodium phosphate, we need to use the rules of solubility and double displacement reactions.
The chemical equation for the reaction between Nickel(II) nitrate (Ni(NO3)2) and sodium phosphate (Na3PO4) is as follows:
Ni(NO3)2 + Na3PO4 → ?
To determine the product, we need to exchange the positive ions (cations) between the two compounds. The cation in Nickel(II) nitrate is Ni2+, and the cation in sodium phosphate is Na+.
Since the cationic charges of both compounds are balanced, we can directly exchange the cations to obtain the product:
Ni(NO3)2 + Na3PO4 → Ni3(PO4)2 + NaNO3
Therefore, the product of the reaction between Nickel(II) nitrate and sodium phosphate is Nickel(II) phosphate (Ni3(PO4)2) and sodium nitrate (NaNO3).
To determine the product of the reaction between nickel(II) nitrate and sodium phosphate, we need to cross-check the charges of the ions and balance the equation, if necessary.
First, let's write the formulas of the compounds involved:
Nickel(II) nitrate: Ni(NO3)2
Sodium phosphate: Na3PO4
Now, we can use the charges on the ions to determine the product.
The nickel(II) ion has a charge of +2, and the nitrate ion has a charge of -1. Therefore, we balance the charges and write the formula for nickel(II) nitrate as Ni(NO3)2.
The sodium ion has a charge of +1, and the phosphate ion has a charge of -3. To balance the charges, we need three sodium ions, resulting in the formula Na3PO4 for sodium phosphate.
Now, we can combine the two compounds and determine the product:
Ni(NO3)2 + Na3PO4 →
To determine the product, we need to interchange the positive ions (cations) between the compounds. Therefore, the nickel(II) ion combines with the phosphate ion, while the sodium ion combines with the nitrate ion.
The product of the reaction is nickel(II) phosphate (Ni3(PO4)2) and sodium nitrate (NaNO3):
Ni(NO3)2 + Na3PO4 → Ni3(PO4)2 + 3NaNO3
Thus, the balanced equation for the reaction between nickel(II) nitrate and sodium phosphate is:
2Ni(NO3)2 + 3Na3PO4 → Ni3(PO4)2 + 6NaNO3
Isnt Nickel(II) phosphate in water solution a precipate? Isnt sodium nitrate soluble?
I suspect the term (aq) needs to be added to your reactants. I will be happy to critique your work.