Friday

October 24, 2014

October 24, 2014

Posted by **Jake** on Monday, January 7, 2008 at 2:03pm.

- Math -
**Damon**, Monday, January 7, 2008 at 2:33pmIf y = f(x) = a x^2 + b x + c

and a, b and c are constants

then you have your parabola.

That IS one.

Now do you want some particular parabola?

for example if I want a parabola that opens up (holds water) and has a vertex at x = 4 and y = -5

Then I can use the form:

(x-h)^2 = 4 g (y-k)

where (h,k) is the vertex and it will open up if g is positive. (by the way g is the distance from the vertex to the focus)

The constant g determines how "steep" it is.

so for our vertex at (4, -5) I have

(x-4)^2 = 4 g (y+5)

for our example let's take g = 1/4 to make it simple

x^2 -8 x +16 = y + 5

y = x^2 -8 x + 11

which is your form that you wanted

**Answer this Question**

**Related Questions**

math - the points (-9,0) and (19,0) lie on parabola. a.) determine an equation ...

Alg II/Trig - A parabola has a vertex at (0,0); a horizontal axis; and the point...

College Algebra - Find the standard form of the equation of the parabola with ...

College Algebra - Find the standard form of the equation of the parabola with ...

Math - If f(x)=3x^2-5x, find the f'(2) & use it to find an equation of tangent ...

pre cal - What is the center of the conic whose equation is x^2 + 2y^2 - 6x + ...

Algebra - I'm trying this again, I'd like the quadratic form, so i can then work...

pre cal - find the standard form of the equation of a parabola with the vertex (...

Math - a parabola has vertex (-6,-12) AND PASSES THROUGH (6,24) find its ...

math - A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) ...