Tuesday

October 21, 2014

October 21, 2014

Posted by **jazz** on Sunday, January 6, 2008 at 11:56pm.

- math -
**Reiny**, Monday, January 7, 2008 at 12:21amSince her year of birth must be divisible by both 23 and 17, it must be divisible by 391, (23 x 17)

Since she is less than 100 she must have been born in the 19hundreds.

So her birth year must be a multiple of 361, it is easy to just try a few multipliers by 361 and I got 1955 = 5*391

Notice that 1955 is only divisible by the primes 5,17, and 23

So if she was born in 1955, then in 2007 she would be 52

- math -
**Reiny**, Monday, January 7, 2008 at 12:32am"So her birth year must be a multiple of 361, it is easy to just try a few multipliers by 361 and I got 1955 = 5*391 "

should have been:

So her birth year must be a multiple of 391, it is easy to just try a few multipliers by 391 and I got 1955 = 5*391

- math -

**Answer this Question**

**Related Questions**

MATH - Let’s agree to say that a positive integer is prime-like if it is not ...

math - Let’s agree to say that a positive integer is prime-like if it is not ...

MATH - TWO INTEGERS ARE DEFINED AS "PARTNERS" IF BOTH OF THEIR PRIME ...

Math - The question is this: You know that a number is divisible by 6 if it is ...

PRE-CALC - A number is selected at random from the set {2, 3, 4, … ,10}. Which ...

Math - Help me!;/ 1) my numerator is 6 less than my denominator. I am equivalent...

math - It is less than 100,000. it's an even number. it is divisible by 2,3, and...

IB HL Math - I need to that if there is better way to prove the following: I am ...

math - number is greater than 50 and less than 100. you can make exactly 5 ...

math - jackie and janice are sisters with the same birthday, different birth ...