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January 30, 2015

January 30, 2015

Posted by **jazz** on Sunday, January 6, 2008 at 11:56pm.

- math -
**Reiny**, Monday, January 7, 2008 at 12:21amSince her year of birth must be divisible by both 23 and 17, it must be divisible by 391, (23 x 17)

Since she is less than 100 she must have been born in the 19hundreds.

So her birth year must be a multiple of 361, it is easy to just try a few multipliers by 361 and I got 1955 = 5*391

Notice that 1955 is only divisible by the primes 5,17, and 23

So if she was born in 1955, then in 2007 she would be 52

- math -
**Reiny**, Monday, January 7, 2008 at 12:32am"So her birth year must be a multiple of 361, it is easy to just try a few multipliers by 361 and I got 1955 = 5*391 "

should have been:

So her birth year must be a multiple of 391, it is easy to just try a few multipliers by 391 and I got 1955 = 5*391

- math -

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