Tuesday

October 21, 2014

October 21, 2014

Posted by **anonymous** on Sunday, January 6, 2008 at 6:09pm.

2sec^2x dx

(cosx)/(sin^3x) dx

calculate the definite integral

interval pi/4, pi/12

csc2xcot2x dx

- calculus -
**Damon**, Sunday, January 6, 2008 at 7:04pmWell, I happen to know that the derivate of the tangent is sec^2 :)

(cosx)/(sin^3x) dx

Try f(x) = 1/sin^2 x

f' = - 2 sin x cos x /sin^4 x

see what happens?

let u = 2 x

then du = 2 dx

and we have

csc u cot u du/2 from u = pi/2 to pi/6

(1/sin u)(cos u/sin u) du/2

= (1/2) (cos u/sin^2 u) du

try 1/sin u

**Answer this Question**

**Related Questions**

Calculus - Hello Everyone, I need help with Calc II. 1. Integral from 0 to 1 of...

Calculus - Use the symmetry of the graphs of the sine and cosine functions as an...

calculus - calculate the indefinite integral (cosx)/(sin^3x)

Calc BC - 1. Find the indefinite integral. Indefinite integral tan^3(pix/7)sec^2...

Integral - That's the same as the integral of sin^2 x dx. Use integration by ...

Calculus II/III - A. Find the integral of the following function. Integral of (x...

Calculus - Solve these indefinite and definite integrals. [integration sign] 4j-...

Calculus - "Leave the answer as a definite integral, but indicate how it could ...

Calculus - Would someone clarify this for me... Is antiderivatives just another ...

Calculus - I have two questions, because I'm preparing for a math test on monday...