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January 28, 2015

January 28, 2015

Posted by **anonymous** on Sunday, January 6, 2008 at 6:09pm.

2sec^2x dx

(cosx)/(sin^3x) dx

calculate the definite integral

interval pi/4, pi/12

csc2xcot2x dx

- calculus -
**Damon**, Sunday, January 6, 2008 at 7:04pmWell, I happen to know that the derivate of the tangent is sec^2 :)

(cosx)/(sin^3x) dx

Try f(x) = 1/sin^2 x

f' = - 2 sin x cos x /sin^4 x

see what happens?

let u = 2 x

then du = 2 dx

and we have

csc u cot u du/2 from u = pi/2 to pi/6

(1/sin u)(cos u/sin u) du/2

= (1/2) (cos u/sin^2 u) du

try 1/sin u

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