Posted by Lucy on Saturday, January 5, 2008 at 5:54pm.
Solve: 3+2(1x) >6 or 2x+14 <=8. Graph the solution set on a number line.
When I solved the equations for the first one I got x<1/2 and for the second one I got x<= 3.
How do I graph the solution set for these????

Algebra II  Damon, Saturday, January 5, 2008 at 6:46pm
for the first one it is everything to the left of 1/2 on your number line.
So put an open circle around 1/2 and an arrow to the left.
The open circle means everything to the left, but not the point itself.
For the second one, the point x = 3 is included so draw a solid, shaded in, circle around that point. Then your arrow points from there to the left. 
Algebra II  Reiny, Saturday, January 5, 2008 at 8:36pm
Damon, since x ≤ 3 is already a subset of
x < 1/2, graphing x < 1/2 the way you just described it would suffice. 
Algebra II  Damon, Saturday, January 5, 2008 at 8:41pm
Oh, I did not realize they were connected by a logical or.