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December 18, 2014

December 18, 2014

Posted by **Lucy** on Saturday, January 5, 2008 at 5:54pm.

When I solved the equations for the first one I got x<-1/2 and for the second one I got x<= -3.

How do I graph the solution set for these????

- Algebra II -
**Damon**, Saturday, January 5, 2008 at 6:46pmfor the first one it is everything to the left of -1/2 on your number line.

So put an open circle around -1/2 and an arrow to the left.

The open circle means everything to the left, but not the point itself.

For the second one, the point x = -3 is included so draw a solid, shaded in, circle around that point. Then your arrow points from there to the left.

- Algebra II -
**Reiny**, Saturday, January 5, 2008 at 8:36pmDamon, since x ≤ -3 is already a subset of

x < -1/2, graphing x < -1/2 the way you just described it would suffice.

- Algebra II -
- Algebra II -
**Damon**, Saturday, January 5, 2008 at 8:41pmOh, I did not realize they were connected by a logical or.

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