Posted by Amy on Friday, January 4, 2008 at 6:57am.
v = 0 + a*t
98 = 12.3 * t
solve for t
v = 0 + a*t again
x = X0 + Vo t +.5 a t^2
.8 = 0 + 0 + (.5) (6.8*10^4 )t^2
t^2 = 2.35 10^-5
t = .00485 seconds in barrel
then use
v = o + a t again
A bullet accelerates at 6.8*10^4 m/s^2 from rest as it travels the 0.80 m of the rifle barrel. How long was then bullet in the barrel? What velocity does the bullet have as it leaves the barrel?
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