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July 23, 2014

July 23, 2014

Posted by **cecile** on Friday, January 4, 2008 at 5:58am.

- maths -
**Damon**, Friday, January 4, 2008 at 7:24amAn = 3 n (2- n^2) / [ 2 n^2 (n+2) ]

An = (3/2) (1/n) (-1) (n^2-2) /(n+2)

as n gets big, 2 looks small

An = (-3/2) (1/n) (n^2/n)

An = -3/2 (n^2/n^2)

An = -3/2

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