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April 20, 2014

April 20, 2014

Posted by **Sam** on Friday, January 4, 2008 at 1:11am.

The question is:

Find the values of C and D if

c/(x-2) + D/(x+1) = 6x/(x^2-x-2)

The answers are: C= 4, D=2

HERE IS MY WORK:

Well, I know that we can add the left side and the denominators become the same. So, the new equations becomes:

c(x+1)+ D(x-2) = 6x

but, how do you go from here to find the values of c and d?

- Algebra -
**drwls**, Friday, January 4, 2008 at 1:24amC/(x-2) + D/(x+1) = 6x/(x-2)(x+1)

Rewrite the terms on the left so that they have the same denominator as the term on the right.

C(x+1) + D(x-2)/[(x-2)(x+1)] =

6x/(x-2)(x+1)

Cx + C + Dx -2D = 6x

This can only be true if C+D= 6 and C-2D = 0

Solve those two equations to get C and D

This is called the method of partial fractions

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