posted by Jake on .
I was wondering if anyone could possible help me with this homework question?
The normal boiling point for acetone is 56.5 degrees C. At an elevation of 5300 ft the atmospheric pressure is 630. torr. What would be the boiling point of acetone (deltahvap = 32.0 kJ/mol) at this elevation? What would be the vapor pressure of acetone at 25.0 degrees C at this elevation?
Use the Clausius-Clapeyron equation.
760 torr is the pressure at the normal boiling point of 56.5. Don't forget that T1 and T2 must be in Kelvin, delta H vap must be in J and R = 8.314 J/mol*K.
Whoops sorry, wrong one.