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September 18, 2014

September 18, 2014

Posted by **Alan** on Wednesday, January 2, 2008 at 5:02pm.

I know the Distance equals rate X Time and I tried using that meathod three times but i keep coming up with a negative time and i know that that is wrong will someone lead me on the right path???

- Algebra II -
**Damon**, Wednesday, January 2, 2008 at 5:10pmname rate time distance

Buggs 40___t_____D

Joan- 50 (t-2)___D

so

40 t = 50(t-2)

40 t = 50 t - 100

-10t = -100

t = +10

- Algebra II -
**DrBob222**, Wednesday, January 2, 2008 at 5:11pmtime it took Joan = X

time it took Buggs = X+2 hrs.

distance each traveled is the same.

distance Joan = r*time = 50t

distance for Buggs = r*time = 40*(X+2)

40*(X+2) = 50X

solve for X = time for Joan.

X+2 = time for Buggs.

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