Saturday

March 28, 2015

March 28, 2015

Posted by **Alan** on Wednesday, January 2, 2008 at 5:02pm.

I know the Distance equals rate X Time and I tried using that meathod three times but i keep coming up with a negative time and i know that that is wrong will someone lead me on the right path???

- Algebra II -
**Damon**, Wednesday, January 2, 2008 at 5:10pmname rate time distance

Buggs 40___t_____D

Joan- 50 (t-2)___D

so

40 t = 50(t-2)

40 t = 50 t - 100

-10t = -100

t = +10

- Algebra II -
**DrBob222**, Wednesday, January 2, 2008 at 5:11pmtime it took Joan = X

time it took Buggs = X+2 hrs.

distance each traveled is the same.

distance Joan = r*time = 50t

distance for Buggs = r*time = 40*(X+2)

40*(X+2) = 50X

solve for X = time for Joan.

X+2 = time for Buggs.

**Answer this Question**

**Related Questions**

Algebra 2 - Bugs made the trip at 40 miles per hour during the first hiatus.joan...

Algebra - Mark made a business trip of 290 miles. He averaged 56 mph for the ...

algebra - Can someoe please help me figure this out? During the first part of a ...

Math - can you help i dnt know what to do so could you tell me how to solve it 1...

Math - On a business trip a salesman traveled 40 mph for the first third of his ...

math sos. - dURING THE FIRST PART OF A TRIP, A CONOEIST TRAVELS53 MILES AT A ...

Algebra - Tom went on a 3 Day road trip in which he drove the same number of ...

algebra - during the first part of a trip, a conoeist travels 70 miles at a ...

Algebra - During the first part of a trip, a canoeist travels 98 miles at a ...

algebra - during the first trip a canoeist travels 79 miles at a certain speed. ...