Posted by **Alan** on Wednesday, January 2, 2008 at 5:02pm.

Buggs made the trip at 40 mph during the first Hiatus. Joan Made the same trip at 50 mph during the second hiatus. How long was the trip if it took Buggs 2 hours longer than it took Joan.

I know the Distance equals rate X Time and I tried using that meathod three times but i keep coming up with a negative time and i know that that is wrong will someone lead me on the right path???

- Algebra II -
**Damon**, Wednesday, January 2, 2008 at 5:10pm
name rate time distance

Buggs 40___t_____D

Joan- 50 (t-2)___D

so

40 t = 50(t-2)

40 t = 50 t - 100

-10t = -100

t = +10

- Algebra II -
**DrBob222**, Wednesday, January 2, 2008 at 5:11pm
time it took Joan = X

time it took Buggs = X+2 hrs.

distance each traveled is the same.

distance Joan = r*time = 50t

distance for Buggs = r*time = 40*(X+2)

40*(X+2) = 50X

solve for X = time for Joan.

X+2 = time for Buggs.

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