Friday
April 18, 2014

Homework Help: calculus

Posted by mathstudent on Monday, December 31, 2007 at 11:54am.

Calculate definite integral of
dx/(x^4 * sqrt(x^2 + 3))
Over (1,3)

I start with the substitution x = sqrt(3)*tan t

so:
sqrt(x^2 + 3) = sqrt(3) * sec t
dx = sqrt(3) * sec^2 t dt
x^4 = 9 * tan^4 t

The integral simplifies to:
= dt/(tan^3 t * sin t)

How do I solve that?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Calculus - Calc length of arc of y=ln(x) from x=1 to x=2 ---- So far: Definite ...
ap calculus - Which of the following definite integrals gives the length of y = ...
calculus - Integrate: dx/sqrt(x^2-9) Answer: ln(x + sqrt(x^2 - 9)) + C I'm ...
Calculus II - Evaluate using u-substitution: Integral of: 4x(tan(x^2))dx ...
Calculus URGENT test tonight - Integral of: __1__ (sqrt(x)+1)^2 dx The answer is...
Calculus - Evaluate the indefinite integral: 8x-x^2. I got this but I the ...
calculus - Assuming that: Definite Integral of e^(-x^2) dx over [0,infinity] = ...
Mathematics - sqrt 6 * sqrt 8 also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So...
Calculus - so we are doing integrals and I have this question on my assignment ...
calc check: curve length - Find the length of the curve y=(1/(x^2)) from ( 1, 1...

Search
Members