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July 28, 2014

July 28, 2014

Posted by **Palma** on Friday, December 28, 2007 at 3:07pm.

- Math -
**Damon**, Friday, December 28, 2007 at 3:15pmthe circumference of the inner circle is 9.5 feet which is 2 pi Rtree where Rtree is the radius of the tree.

From that find

Rtree = 9.5 /(2*pi)

then you can find the area of the tree cross section

Atree = pi Rtree^2

Then

the outer radius of the path is

Rout = Rtree + 2

and the area of the big circle, which includes the tree cross section is:

pi Rout^2

the difference is the area of the garden

pi(Rout^2 - Rtree^2)

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