Posted by Palma on Friday, December 28, 2007 at 3:07pm.
the circumference of the inner circle is 9.5 feet which is 2 pi Rtree where Rtree is the radius of the tree.
From that find
Rtree = 9.5 /(2*pi)
then you can find the area of the tree cross section
Atree = pi Rtree^2
Then
the outer radius of the path is
Rout = Rtree + 2
and the area of the big circle, which includes the tree cross section is:
pi Rout^2
the difference is the area of the garden
pi(Rout^2 - Rtree^2)
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