Sunday
March 26, 2017

Post a New Question

Posted by on .

How many joules are needed to heat 8.50 grams of ice from -10.0 degrees C to 25.0 degrees C?

  • Chemistry - ,

    q1 = heat necessary to change ice from -10 to zero = mass x specific heat ice x (Tfinal - Tinitial) where Tfinal is zero and Tinitial is -10.

    q2 = heat necessary to melt ice but stay at zero = mass x heat fusion of ice.

    q3= heat necessary to heat water at zero to 25 C. = mass x specific heat water x (25-0).
    total = q1 + q2 + q3.
    Post your work if you get stuck.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question