Wednesday

July 30, 2014

July 30, 2014

Posted by **Jenny** on Wednesday, December 19, 2007 at 9:37pm.

A survey of an urban university (population of 25,450) showed that 750 of 1100 students sampled attended a home football game during the season. What inferences can be made about student attendance at football games?

Using the 99% level of confidence, what is the confidence interval?

a. [0.767, 0.814]

b. [0.0.6550, 0.7050]

c. [0.6659, 0.6941]

d. [0.0.6795, 0.6805]

- Statistics -
**economyst**, Thursday, December 20, 2007 at 11:40amI believe the answer is 'none of the above'

The formula for the confidence interval is:

P +or- Z(99) * sqrt(P*Q/n)

P is the estimated probability of attendence = 750/1100 = .6818

Q = 1-P

n = sample size = 1100

Z(99) is the number of standard deviations away from the mean that 99% of the population fall = 2.575

So Z(99)*sqrt(P*Q/n) = .03616.

So the range should be (.6456, .7180)

**Related Questions**

uog - A survey of an urban university (population of 25,450) showed that 750 of ...

Statistics - A survey of an urban university (population of 25,450) showed that ...

Math-statistics - During the 2000 season, the home team won 138 of the 240 ...

Math Statistics - Students enrolled in an introductory statistics course at a ...

Math - Laura takes a random survey of the students in her school. Of the 48 ...

stats - A survey was done recently by the Royal Bank with Ipsos Reid (reported ...

math help - A survey was done recently by the Royal Bank with Ipsos Reid (...

statistic - A survey of households in a small town showed that in 500 of 1,200 ...

statistics - A group of statistics students decided to conduct a survey at their...

Statistics - A survey of 815 students is asked whether or not they have cable TV...