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November 20, 2014

November 20, 2014

Posted by **freddie** on Tuesday, December 18, 2007 at 10:22pm.

- math(trig) -
**DrBob222**, Tuesday, December 18, 2007 at 11:11pmIs that t5an A a typo? I assume it should read tan A = 2.

I don't know how your triangle is labeled but tan = side opposite the angle divided by side adjacent to the angle. One of those sides will be the 30 yards and you can solve for the other one. Then (one side)^{2}+ (other side)^{2}= (hypotenuse)^{2}

- math(trig) -
**drwls**, Wednesday, December 19, 2007 at 1:05amtanA = a/b = 2

(a is the side opposite A, and b is the side perpendicular to a.)

If a = 30, then b = a/2 = 15.

c = sqrt [(30^2 + (15)^2] = 33.54 yd

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