Posted by **Lindsay** on Monday, December 17, 2007 at 10:58pm.

I still cannot solve this problem:

Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from each celestial body exactly cancel, leaving the craft literally weightless. Take the distance between the centers of the Earth and Moon to be 3.90E+5 km and the Moon-to-Earth mass ratio to be 1.200E-2. What is the spaceship's distance from the center of the Moon?

Bobpursely told me that:

Mm/Me=(d2/d)^2

where mm is mass moon, me mass earth, d2 is distance from craft to moon, and d is the distance from craft to earth.

My online homework site wants me to use ONLY the info given and solve for what I don't have. So I'm trying to get the distance from the craft to earth using the numbers given, but I can't seem to figure it out.

## Answer This Question

## Related Questions

- physics - still cant get this one? so damon i know you wanna help! or anyone ...
- PHYSICS - Consider a spaceship located on the Earth-Moon center line (i.e. a ...
- Physics - Consider a spaceship located on the Earth-Moon center line (i.e. a ...
- physics hey damon one more please! =] - Consider a spaceship located on the ...
- Physics - Consider a spaceship located on the Earth-Moon center line (i.e. a ...
- PHYSICSS!!! - still cant get this one? so damon i know you wanna help! or ...
- Calculus Physics - Imagine a spaceship on its way to the moon from the earth. ...
- physics - magine a straight line connecting the centers of the earth and the ...
- Physics - A spaceship of mass 175,000 kg travels from the Earth to the Moon ...
- Physics - A satellite is placed between the Earth and the Moon, along a straight...

More Related Questions