A student librarian picks up a 2.2 kg book from the floor to a height of 1.15 m. He carries the book 8.0 m to the stacks and places the book on a shelf that is 0.35 m above the floor. How much work does he do on the book?

how do i do this??

(2.2 x 0.35)g Joules. Don't forget the g = 9.8 m/s^s. Only the elevation change (final - initial) matters when calculating the work done.

To calculate the work done by the student librarian on the book, you need to use the formula:

Work = Force × Distance × cos(θ)

In this case:
- The force is the weight of the book, which can be calculated as the mass of the book multiplied by the acceleration due to gravity (9.8 m/s²).
- The distance is the vertical distance the book is raised and the horizontal distance it is carried.
- θ is the angle between the force and the direction of motion (in this case, it is 0° since the force is vertical).

Let's break down the steps to calculate the work:

1. Calculate the weight of the book:
Weight = mass × acceleration due to gravity
Weight = 2.2 kg × 9.8 m/s²

2. Calculate the work done to raise the book:
Work_raising = Force × Distance_raised × cos(θ)
Distance_raised = 1.15 m
Work_raising = Weight × Distance_raised × cos(0°)

3. Calculate the work done to carry the book horizontally:
Work_horizontal = Force × Distance_horizontal × cos(θ)
Distance_horizontal = 8.0 m
Work_horizontal = Weight × Distance_horizontal × cos(0°)

4. Calculate the total work:
Total Work = Work_raising + Work_horizontal

By substituting the values into the equations, you can find the answer.