Posted by Karinna on Sunday, December 16, 2007 at 11:58pm.
The tricky part is the number of ways (combinations) of choosing 2 DIFFERENT desserts from 13. It does not matter in what order the two desserts are picked. That number of combinations is
13!/(11!*2!) = (13*12)/2 = 78.
We are assuming that they are required to have two different desserts. Zero or one dessert is "not an option", as they say.
Now multiply that 78 by the possible number of main dishes (8) and the number of vegetable dishes (10). You will get the answer.
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